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Q.

If  x1,x2,x3..........xn are sequence of integers such that 1xi2  and  x1+x2+x3+.......+xn=19x12+x22+x32+.......+xn2=99  then maximum  value  of(x13+x23+.......+xn3)minimum  value  of(x13+x23+.......+xn3)   is _______

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answer is 7.

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Detailed Solution

-1, 1, 2 are integers to be used for  
Suppose (1)  used  xtimes                    1  used  ytimes                   2  used  ztimes}then   x(1)+y(1)+z(2)=19(1)x(1)2+y(1)2+z(2)2=99(2)
On solving  x+z=40
2y+6z=118
y=593z0
z19.2
Let us find out min and max value of  x(1)3+y(1)3+z(2)3
 =x+y+8z
  =z40+593z+8z
  =6z+19min19
    max19(7)           
 

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