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Q.

If x1, x3 are the roots of ax2 – 6x + 1 = 0 and x2, x4 are the roots of 21x2–bx+1 = 0; x1, x2, x3, x4 are in H.P. then (a, b) =

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a

(–5, 10)

b

(3, 8)

c

(5, 10)

d

(3, –10)

answer is C.

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Detailed Solution

The given equations are ax2 – 6x + 1 = 0.....(i), 

and 21x2–bx+1 = 0....(ii)

the roots of eq.(i) are  x1, x3

the roots of eq.(ii) are x2, x4

and given that x1, x2, x3, x4 are in H.P.

1x11x3=1x21x4364a=b284b2=1204a

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If x1, x3 are the roots of ax2 – 6x + 1 = 0 and x2, x4 are the roots of 21x2–bx+1 = 0; x1, x2, x3, x4 are in H.P. then (a, b) =