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Q.

If (x+2)  is the G.C.D of the polynomials (x4)(2x2+xa)  and (x+1)(2x2+bx12),  then the value of (5a6b)  is

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a

42

b

24

c

24

d

42

answer is B.

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Detailed Solution

(x+2)  is G.C.D  of f(x)  and g(x)f(2)=0;g(2)=0f(2)=82a=0a=6

g(2)=2b=4b=2

5a6b=5(6)6(2)=42

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