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If x² +4y² –8x+12 = 0 is satisfied by real values of x and y then $^{'} y^{'} \in$

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[2,5]

[-1,1]

[2,6]

[-2,-1]

answer is C.

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Detailed Solution

$x^{2} - 8 x + (4 y^{2} + 12) = 0 is a quadratic in ' x' , ' x' is real then discriminate \geq 0$ $Δ \geq 0 \Rightarrow y^{2} - 1 \leq 0$

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