If x32x-1x+2x-3=A+B2x-1+Cx+2+Dx-3⇒A=

x32x-1x+2x-3=A+B2x-1+Cx+2+Dx-3 x32x-1x+2x-3=x32x-1x2-x-6 =x32x3-3x2-11x+6 improper fraction A=12

If x32x-1x+2x-3=A+B2x-1+Cx+2+Dx-3⇒A=

x32x-1x+2x-3=A+B2x-1+Cx+2+Dx-3 x32x-1x+2x-3=x32x-1x2-x-6 =x32x3-3x2-11x+6 improper fraction A=12

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

$If \frac{x^{3}}{(2 x - 1) (x + 2) (x - 3)} = A + \frac{B}{2 x - 1} + \frac{C}{x + 2} + \frac{D}{x - 3} \Rightarrow A =$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$- \frac{8}{25}$

$\frac{27}{25}$

$- \frac{1}{50}$

$\frac{1}{2}$

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\frac{x^{3}}{(2 x - 1) (x + 2) (x - 3)} = A + \frac{B}{2 x - 1} + \frac{C}{x + 2} + \frac{D}{x - 3} \frac{x^{3}}{(2 x - 1) (x + 2) (x - 3)} = \frac{x^{3}}{(2 x - 1) (x^{2} - x - 6)} = \frac{x^{3}}{2 x^{3} - 3 x^{2} - 11 x + 6} i m p r o p e r f r a c t i o n A = \frac{1}{2}$