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Q.

If x=sin130°+cos130° then

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a

x>0

b

x0

c

x=0

d

x<0

answer is C.

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Detailed Solution

x=2[12sin130+12cos130]

=2[sin130.cos45+sin45.cos130]

=2[sin(130+45)]

=2sin175=2sin(1805)

=2sin5

x>0

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