If $x=\sin 1,y=\sin 2;z=\sin 3$  then

$y=\sin 2=\sin \left[\pi -\left(\pi -2\right)\right]=\sin \left[\pi -2\right]=\sin \left(1.14\right)$

$z=\sin 3=\sin \left[\pi -\left(\pi -3\right)\right]=\sin \left[\pi -3\right]=\sin \left(0.14\right)$

$\sin 1.14>\sin 1>\sin 0.14$

$y>x>z\left[\sin \theta \text{ invcreasing in }{Q}_1\right]$

$z<x<y$