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Q.

If x+y=17 and x2+y2=167, what is the value of xy?


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a

17+4114

b

61

c

48+167

d

122 

answer is B.

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Detailed Solution

Given,
x+y=17…. (1)
x2+y2=167…. (2)
Square both side of the first equation,
(x+y)2=172 .
x2+y2+2xy=289  (Since,(a+b)2=a2+2ab+b2.)
167+2xy=289                          (From equation 2)
2xy=289-167
2xy=122
xy=61
This is the value of xy.
The correct option is 2.
 
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If x+y=17 and x2+y2=167, what is the value of xy?