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Q.

If y = ex . cot x then dydx will be

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a

excot x

b

ex cosec2x

c

ex[cot x – cosec2x]

d

excot x – cosec2x

answer is C.

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Detailed Solution

y=excotxdydx=exddx(cotx)+cotxddxex=excosec2x+cotxex=excotxcosec2x

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