Q.

If y = y(x) is the solution of the differential equation dydx+y .tanx=sinx, 0xπ3, with y(0)=0, then yπ4 is equal to

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a

12loge2

b

122loge2

c

14loge2

d

loge2

answer is B.

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Detailed Solution

dydx+ytanx=sinxI.F=etanxdx=elogsecx=secxSolution  isy(I.F)=sinx(I.F)dxysecx=sinxsecxdx=tanxdx=log|secx|+cputx=0

y(0)sec0=log|sec0|+cc=0ysecx=log|secx|putx=π4y(π4)secπ4=log|secπ4|y(π4)2=log2y(π4)=122log2

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