Q.

If y=xlogxloglogx, then dydx=

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

yxInxInx2+2Inlogx

b

yxInxx1+2InInlogx

c

yxlogylogx2loglogx+1

d

yxlogxloglogx2loglogx+1

answer is B, D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

y=xlogxloglogx,

logy=logxloglogx×logx

Taking log of both sides, we get

log(logy)=log(logx)+log(logx)log(logx)

Differentiating w.r.t.x, we get

1logy1ydydx=1xlogx+2log(logx)logx1x=2log(logx)+1xlogxordydx=yxlogylogx(2log(logx)+1)

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
If y=xlogxloglogx,  then dydx=