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If $y = 2 \sin [\frac{πt}{2} + ϕ]$ , where y is in cm then what is the maximum acceleration of the particle doing the SHM?

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$\frac{π^{2}}{4} c m / s^{2}$

$\frac{π}{4} c m / s^{2}$

$\frac{π^{2}}{2} c m / s^{2}$

$\frac{π}{2} c m / s^{2}$

answer is B.

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Detailed Solution

$ω = \frac{π}{2} r a d / s a n d A = 2 c m$

$M a x i m u m a c c e l e r a t i o n = ω^{2} A = \frac{π^{2}}{2} c m / s^{2}$

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