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Q.

If z = (3 + 7i) (a + ib) where a,bZ{0}, is purely imaginary, then the minimum value of |z| is

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a

74

b

45

c

58

d

65

answer is C.

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Detailed Solution

z=(3a7b)+i(3b+7a)

For z to be purely imaginary we have

3a=7ba=7 or b=3 (for least value of |z| ) |z|=58 

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