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Q.

If  z0zsinfxdx=z+20zxsinfxdx where z > 0, then  1+zf|zcotfz is equal to

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a

0

b

1

c

2

d

3

answer is D.

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Detailed Solution

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 0zsinfx1xdx=z2+zsinfz
differentiate both sides w.r.t ‘z’
 sinfz1z=2z+1sinfz+z2+zcosfzf|z 3zsinfz=z2+zcosfzf|z 3=z+1cotfz.f|z
 

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