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Q.

If  z=122i  is such that  |z+1|=αz+β(1+i),i=1  and  α,βR  then eccentricity of  the ellipse whose lengths of major and minor axes are  equal  β,α  respectively is  

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a

52

b

32

c

12

d

23

answer is B.

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Detailed Solution

 Z=122iZ+1=322i |Z+1|=αZ+β(1+i) 94+9=α22αi+β+βi
Equating real and imaginary parts on both sides
 β2α=0and52=α2+β α=1,β=2,α+β=3

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