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If $|Z_{1}| = 1, |Z_{2}| = 2, |Z_{3}| = 3$ and $|9 Z_{1} Z_{2} + 4 Z_{1} Z_{3} + Z_{2} Z_{3}| = 12$ then the value of $|Z_{1} + Z_{2} + Z_{3}|$ is

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answer is D.

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Detailed Solution

${|z_{1}|}^{2} = 1, \to z_{1} {\bar{z}}_{1} = 1$

Similarly $z_{2} . {\bar{z}}_{_{2}} = 4$ , $z_{3} . {\bar{z}}_{_{3}} = 3$

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