If Z₁ and Z₂ are the impedances of the given circuits (a) and (b) as shown in figures, then choose the correct option

 

From the values given in question;
Impedence of circuit (a) is ${\mathrm{Z}}_1=\mathrm{R}=10 \mathrm{\Omega }$
Impedence of circuit (b) is
$\begin{array}{l}{\mathrm{z}}_2=\sqrt{{\mathrm{R}}^2+{\left(\frac{1}{\mathrm{C\omega }}\right)}^2}\ln \mathrm{fig}\left(\mathrm{b}\right)\\ =\sqrt{{\mathrm{R}}^2+{\left(\frac{{10}^6}{\frac{{10}^3}{\mathrm{\pi }}2\mathrm{\pi }50}\right)}^2}\\ =\sqrt{{10}^2+{10}^2}=10\sqrt{2}\end{array}$
Therefore, it is clear that z₂ > z₁
(2) ${\mathrm{Z}}_1+{\mathrm{Z}}_2=(10+10\sqrt{2})\mathrm{\Omega }\ne 20\mathrm{\Omega }$
(3) ${\mathrm{Z}}_1\ne {\mathrm{Z}}_2$
(4) ${\mathrm{z}}_1>{\mathrm{z}}_2$is also false.