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Q.

If Z1,Z2,Z3 are complex number such that  z1=2,z2=3,z3=4then maximum value    of z1z22+z2z32+z3z12 is

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a

29

b

87

c

58

d

83

answer is C.

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Detailed Solution

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z1z22+z2z32+z3z12=2z12+z22+z32z1z¯2+z¯1z2+z2z¯3+z¯2z3+z3z¯1+z¯3z1=58z1z¯2+z¯1z2+z2z¯3+z¯2z3+z3z¯1+z¯3z1Nowz1+z2+z320z12+z22+z32+z1z¯2+z¯1z2+z2z¯3+z¯2z3+z3z¯1+z¯3z10z1z¯2+z¯1z2+z2z¯3+z¯2z3+z3z¯1+z¯3z129
from (1) and (2),   maximum value = 58 + 29 = 87.

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If Z1,Z2,Z3 are complex number such that  z1=2,z2=3,z3=4then maximum value    of z1−z22+z2−z32+z3−z12 is