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Q.

If |z1|<2|z2|  then the locus of z=x+iy  is

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a

x2+y2+3x2=0

b

3x2+3y214x+15>0

c

3x2+3y214x+15<0

d

3x2+3y214x+15=0

answer is B.

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Detailed Solution

|z1|<2|z2|

(x1)2+y2<4(x2)2+4y2

3x2+3y214x+15>0

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