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Q.

If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than five times her actual age. What is her age now?


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a

15 years

b

14 years

c

41 years

d

16 years 

answer is B.

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Detailed Solution

It is given that if Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than five times her actual age.
Let x be the age of Zeba.
According to the given condition,
xβˆ’5 2 =11+5x β‡’ x 2 +25βˆ’10x=11+5x β‡’ x 2 +25βˆ’11βˆ’10xβˆ’5x=0 β‡’ x 2 βˆ’15x+14=0   On factoring it, we get,
β‡’ x 2 βˆ’15x+14=0 β‡’ x 2 βˆ’14xβˆ’x+14=0 β‡’x xβˆ’14 βˆ’1 xβˆ’14 =0 β‡’ xβˆ’1 xβˆ’14 =0 β‡’x=1,14   The age cannot be 1 as the age before 5 years will make no sense.
So, x=1 is neglected.
Thus, the age of Zeba is 14 years.
Hence, the correct option is 2.
 
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