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Q.

If 0.15 g of a solute dissolved in 15 g of solvent is boiled at a temperature higher by 0.216° C than that of the pure solvent. The molecular weight of the substance ( molal elevation constant for the solvent is 2.16∘Ckg/mol is 

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a

100

b

1.01

c

10

d

10.1

answer is D.

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Detailed Solution

m=Kb×w×1000ΔTb×W=2.16×0.15×10000.216×15=100

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