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Q.

 If 0<α,β,γ<π/2 such that α+β+γ=π2 and cotα, cotβ, cotγ  are in arithmetic progression, then  the value of  cotα·cotγ  is 

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a

1

b

3

c

cot2β

d

cotα+cotγ

answer is B.

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Detailed Solution

cotα,cotβ,cotγ are in A.P.cotα+cotγ=2cotβ

Also α+β+γ=π2α+γ=π2β. so that  cot (α+γ)=cotπ2βcotαcotγ1cotα+cotγ=1cotβcotαcotγ1=2cotαcotγ=3

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