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Q.

If λ0 and  λ are the threshold wavelength and the wavelength of the incident light respectively on a metal surface, the velocity of the photoelectron ejected from the metal surface is (me = mass of electron, h = Planck's constant, c = speed of light) :

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a

2hme1λ0−1λ

b

2hλ0−λme

c

2hcλ0−λme

d

2hcmeλ0−λλλ0

answer is C.

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Detailed Solution

It is known that;

hcλ=hcλ0+12mev2

On solving v=2hcmeλ0−λλλ0.

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