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Q.

 If Δ1,Δ2 are the areas of incircle and circumcircle of a triangle with sides 3,4 and 5 then Δ1Δ2=

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Detailed Solution

r=ΔSr=1 s=a+b+c2=122=6

Δ=rs=6Δ1Δ2=1(5h)2=425

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