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Q.

If 1, ω, ω2 are the cube roots of unity, then
(2-ω)(2-ω2)(2-ω10)(2-ω11)=

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a

7

b

36

c

49

d

6

answer is C.

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Detailed Solution

w10=(w3)3.w=w,  w11=(w3)3.w2=w2

  (2-w) (2-w2) (2-w10) (2-w11)

  (2-w) (2-w2) (2-w) (2-w2)

 =(2-w) (2-w2)2

 =(4-2w2-2w+w3)2

5-2ω+ω22=72=49

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