If 1.50 g of H2C2O4⋅2H2O were heated to drive off the water of hydration, how much anhydrous H2C2O4 would remain?

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If $1.50 g$ of $H_{2} C_{2} O_{4} \cdot 2 H_{2} O$ were heated to drive off the water of hydration, how much anhydrous $H_{2} C_{2} O_{4}$ would remain?

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$1.07 g$

$0.92 g$

$0.34 g$

$1.50 g$

answer is C.

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Detailed Solution

Anhydrous $H_{2} C_{2} O_{4}$ would remain

$\frac{1.5}{126} \times 90 = 1.07 g$

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