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Q.

If 16sinx,cosx,tanx  are in G.P., then r is equal to

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a

nπ±π3,nZ

b

none of these

c

2nπ±π3,nZ

d

nπ+(1)nπ3,nZ

answer is B.

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Detailed Solution

It is given that 16sinx,cosx,tanx are in GP

 cos2x=16sinx tanx

6cos2x=sinx tanx

 6cos3x+cos2x1=0 cosx126cos2x+4cosx+2=0

 cosx=12cos2x+4cosx+2=0 has imaginary roots 

 cosx=cosπ3 x=2nπ±π3,nZ.

 

 

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