Q.

If λ1 and λ2 are the wavelengths of the first members of the Lyman and Paschen series, respectively, then λ1 : λ2 is

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a

7 : 50

b

7 : 108

c

1 : 3

d

1 : 30

answer is D.

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Detailed Solution

1λα1n121n22 λ1λ2=132142Paschen112122=7/1443/4=7108

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