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Q.

If =1cos θ1-cos θ1cos θ-1-cos θ1, then  lies in the interval

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a

2, 4

b

1, 4

c

-1, 1

d

2, 4

answer is B.

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Detailed Solution

=1cos θ1-cos θ1cos θ-1-cos θ1R1R1+R3 =002-cosθ1cosθ-1-cosθ1 =2cos2θ+1 =2cos2θ+2  wkt,  0cos2θ102cos2θ222cos2θ+24    lies in [2, 4]

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