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If $1 M$ and $2.5$ litre $NaOH$ solution is mixed with another $0.5 M$ and 3 litre $NaOH$ solution, then molarity of the resultant solution will be

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$0.50 M$

$0.80 M$

$1.0 M$

$0.73 M$

answer is B.

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Detailed Solution

M₁V₁+M₂V₂=MV
$(2 .5 \times 1 + 3 \times 0 .5) = M \times 5 .5$

$2 .5 + 1 .5 = M \times 5 .5 M = \frac{4}{5 .5} = 0 .73 M$

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