If $\sqrt{\frac{1+\mathrm{SinA}}{1-\mathrm{SinA}}}=\mathrm{SecA} + \mathrm{TanA} ,$ then the quadrants in which the angle $\mathrm{A}$ lies are

$\begin{array}{rcl}\sqrt{\frac{1+\sin \mathrm{A}}{1-\sin \mathrm{A}}}& =& \sec \mathrm{A}+\tan \mathrm{A}\\ \frac{1+\sin \mathrm{A}}{1-{\sin }^2\mathrm{A}}& =& \sec \mathrm{A}+\tan \mathrm{A}\\ \frac{1+\sin \mathrm{A}}{|\cos \mathrm{A}|}& =& \sec \mathrm{A}+\tan \mathrm{A}\end{array}$

$\cos \mathrm{A}$ Positive in ${\mathrm{Q}}_1, {\mathrm{Q}}_4$