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Q.

If θ=π21, then sin23θsin7θsin2θ+sin14θ=

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a

2

b

1

c

-1

d

4

answer is A.

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Detailed Solution

θ=π21

sin23θsin7θsin2θ+sin14θ

=sin23π21sin7π21sin2π21+sin14π21

=sin(π+2π21)sinπ3sin2π21+sin(ππ3)

=sin2π21sinπ3sin2π21+sinπ3

=1(sin2π21+sinπ3)sin2π21+sinπ3

=1

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