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If $(- 2, 2), (1, 0), (x, 0), (1, y)$ forms a parallelogram, then $(x, y) =$

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$(- 4, 2)$

$(- 4, - 2)$

$(4, - 2)$

$(4, 2)$

answer is D.

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Detailed Solution

$(- 2, 2), (1, 0), (x, 0), (1, y)$

$(\frac{- 2 + x}{2}, \frac{2 + 0}{2}) = (\frac{1 + 1}{2}, \frac{0 + y}{2})$

$(\frac{- 2 + x}{2}, 1) = (1, \frac{y}{2})$

$- 2 + x = 2 y = 2$

$x = 4 y = 2$

$(x, y) = (4, 2)$

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