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Q.

If $270^{\circ} < θ < 360^{\circ} and cos θ =5/13then \frac{13 \sin θ + 5 \tan θ}{12 \cot θ - 5 \sec θ} =$

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a

$\frac{- 4}{3}$

b

$\frac{3}{4}$

c

$\frac{4}{3}$

d

$\frac{- 3}{4}$

answer is C.

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Detailed Solution

Question Image

$θ & Q_{4}, \cos θ = \frac{5}{13}$

$\sin θ = \frac{- 13}{13}, \tan θ = \frac{- 12}{5}$

$\cot θ = \frac{- 5}{12}, \sec θ = \frac{13}{5}$

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If 270∘<θ<360∘and cosθ=5/13then 13sinθ+5tanθ12cotθ−5secθ=