If $\frac{π}{2}$ and $\frac{π}{4}$ are the arguments of $z_{1} and z_{2}$ respectively, then $Arg (\frac{z_{1}}{z_{2}}) =$

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$\frac{3 π}{4}$

$\frac{π}{3}$

$\frac{π}{4}$

$π$

answer is A.

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Detailed Solution

$A r g z_{1} = \frac{π}{2}, A r g z_{2} = \frac{π}{4} \Rightarrow A r g z_{2} = \frac{- π}{4} \Rightarrow A r g z_{1} - A r g z_{2} = \frac{π}{2} + \frac{π}{4} = \frac{3 π}{4} ∴ A r g \frac{z_{1}}{z_{2}} = \frac{3 π}{4}$

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