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Q.

$(i) F_{2} + NaOH (dil.) \to 2 NaF + H_{2} O + X$
$(ii) F_{2} + NaOH (conc.) \to NaF + H_{2} O + Y$

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a

${OF}_{2} and {OF}_{2}$

b

${OF}_{2} and O_{2}$

c

$O_{2} F_{2} and O_{2}$

d

$O_{2} F_{2} and {OF}_{2}$

answer is D.

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Detailed Solution

detailed_solution_thumbnail

$(i) 2 F_{2} + 2 NaOH (dil.) \to 2 NaF + H_{2} O + {OF}_{2}$

$(ii) 2 F_{2} + 4 NaOH (conc .) \to 4 NaF + 2 H_{2} O + O_{2}$

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(i) F2+NaOH( dil. )→2NaF+H2O+X (ii) F2+NaOH( conc. )→NaF+H2O+Y