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Q.

If  2nC3:nC2=44:3, hen for which of the following values of r, the value of  nCr will be 15 ?

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a

r=5

b

r=3

c

r=6

d

r=4

answer is B.

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Detailed Solution

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(2n)!(2n3)!3!×2!×(n2)!n!=443  (2n)(2n1)(2n2)3n(n1)=443 4(2n1)=44 2n=12 n=6

Now,  6Cr=15 6Cr=6C2

or  6C4

 r=2,4

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If  2nC3:nC2=44:3, hen for which of the following values of r, the value of  nCr will be 15 ?