Q.

If 2tanθ=secθ , then 4cot2θ3tan2θ=

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answer is 11.

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Detailed Solution

2tanθ=secθ

2sinθcosθ=1cosθ

2sinθ=1

sinθ=12

sinθ=sin30°

θ=30°

4cot2θ3tan2θ=4cot230°3tan230°

=4(32)3132

=4×31=121=11

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