Q.

If 2x2 + 5xy + 2y2  11x 7y+ k= 0 is the pair
of asymptotes of the hyperbola 2x2 + 5xy + 2y211x7y4 = 0 then k = 

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a

6

b

3

c

4

d

5

answer is C.

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Detailed Solution

Given hyperbola 2x2+5xy+2y2-11x-7y-4=0 Now equation of pair of asymptotes is 2x2+5xy+2y2-11x-7y+k=0 since it represents a pair of lines then =0 abc+2fgh-af2-bg2-ch2=0 2(2)(k)+2-72-11252-2-722-2-1122-k522=0 4k+3854-984-2424-25k4=0 16k+385-98-242-25k=0 -9k+45=0 -9k=-45 k=5  Equation of pair of asymptotes is 2x2+5xy+2y2-11x-7y+5=0

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If 2x2 + 5xy + 2y2 – 11x –7y+ k= 0 is the pairof asymptotes of the hyperbola 2x2 + 5xy + 2y2–11x–7y–4 = 0 then k =