Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

If 2x2 + 5xy + 2y2  11x 7y+ k= 0 is the pair
of asymptotes of the hyperbola 2x2 + 5xy + 2y211x7y4 = 0 then k = 

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

6

b

3

c

4

d

5

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Given hyperbola 2x2+5xy+2y2-11x-7y-4=0 Now equation of pair of asymptotes is 2x2+5xy+2y2-11x-7y+k=0 since it represents a pair of lines then =0 abc+2fgh-af2-bg2-ch2=0 2(2)(k)+2-72-11252-2-722-2-1122-k522=0 4k+3854-984-2424-25k4=0 16k+385-98-242-25k=0 -9k+45=0 -9k=-45 k=5  Equation of pair of asymptotes is 2x2+5xy+2y2-11x-7y+5=0

Watch 3-min video & get full concept clarity

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon