If ∫π/2x 3−2sin2⁡zdz+∫0y cos⁡tdt=0 then dydx at (π/2,π) is

Differentiating w ·r· t· x, we get3−2sin2⁡x+dydxcos⁡y=0Putting x=π/2 and y=π we getdydx(π/2,π)=1.

If ∫π/2x 3−2sin2⁡zdz+∫0y cos⁡tdt=0 then dydx at (π/2,π) is

Differentiating w ·r· t· x, we get3−2sin2⁡x+dydxcos⁡y=0Putting x=π/2 and y=π we getdydx(π/2,π)=1.

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If $\int_{π / 2}^{x} \sqrt{3 - 2 \sin^{2} z} d z + \int_{0}^{y} \cos t d t = 0$ then $\frac{d y}{d x} at (π / 2, π)$ is

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Differentiating w ·r· t· x, we get

$\sqrt{3 - 2 \sin^{2} x} + \frac{d y}{d x} \cos y = 0$

Putting $x = π / 2$ and $y = π$ we get

${\frac{d y}{d x}]}_{(π / 2, π)} = 1 .$

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If ∫π/2x 3−2sin2⁡zdz+∫0y cos⁡tdt=0 then dydx at (π/2,π) is

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If $\int_{π / 2}^{x} \sqrt{3 - 2 \sin^{2} z} d z + \int_{0}^{y} \cos t d t = 0$ then $\frac{d y}{d x} at (π / 2, π)$ is