If 2x+3x+1x-3=ax+1+bx-3, then a+b

2x+3x+1x-3=ax+1+bx-3 ⇒2x+3=ax-3+bx+1 Put x=-1; 2(-1)+3=a(-1-3)⇒1=-4a⇒a=-14 Now put x=3; 23+3=b(3+1)⇒9=4b⇒b=94 Therefore, a+b=-14+94=2.

If 2x+3x+1x-3=ax+1+bx-3, then a+b

2x+3x+1x-3=ax+1+bx-3 ⇒2x+3=ax-3+bx+1 Put x=-1; 2(-1)+3=a(-1-3)⇒1=-4a⇒a=-14 Now put x=3; 23+3=b(3+1)⇒9=4b⇒b=94 Therefore, a+b=-14+94=2.

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

If $\frac{2 x + 3}{(x + 1) (x - 3)} = \frac{a}{x + 1} + \frac{b}{(x - 3)}, then a + b$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$2$

$- 1 / 4$

$1$

$9 / 4$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\frac{2 x + 3}{(x + 1) (x - 3)} = \frac{a}{x + 1} + \frac{b}{(x - 3)} \Rightarrow 2 x + 3 = a (x - 3) + b (x + 1) Put x = - 1; 2 (- 1) + 3 = a (- 1 - 3) \Rightarrow 1 = - 4 a \Rightarrow a = \frac{- 1}{4} Now put x = 3; 2 (3) + 3 = b (3 + 1) \Rightarrow 9 = 4 b \Rightarrow b = \frac{9}{4} Therefore, a + b = \frac{- 1}{4} + \frac{9}{4} = 2 .$