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If $3 [\begin{array}{ll} a b \\ c d \end{array}] = [\begin{array}{cc} a & b \\ - 1 & 2 d \end{array}] + [\begin{array}{cc} 4 & a + b \\ c + d & 3 \end{array}]$ , then $a + b + c + d =$

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answer is B.

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Detailed Solution

$3 a = a + 4, 3 b = b + a + b$

$3 c = - 1 + c + d, 3 d = 2 d + 3$

On solving we get, $a = 2, b = 2, c = 1, d = 3, a + b + c + d = 8$

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