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Q.

If 3e− can be accommodated in each orbital, then bow many elements will be present in the 7th period of periodic table?

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answer is 48.

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Detailed Solution

The total number of orbital is found as,

No. of orbitals =1+3+5+7=16

The total number of the element when 3e− can be accommodated in each orbital

16×3=48

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