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Q.

If 3+i100=299p+iq, then p and q are roots of the equation

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a

x2-3+1x+3=0

b

x2+3-1x-3=0

c

x2+3+1x+3=0

d

x2-3-1x-3=0

answer is B.

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Detailed Solution

3+i100=299(p+q)

32+i2100=p+iq2

p+iq2=cosπ6+i sinπ6100

p+iq2=cos 50π3+i sin 50π3

p+iq2=cos16π+2π3+i sin16π+2π3

 =cos 2π3+i sin 2π3

 =-12+i32

 

p=-1,  q=3

The quadratec equation whose roots are p, q is

x2-x(p+q)+pq=0 x2-x3-1-3=0

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