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Q.

If3x2+4kx+1>0forallrealvaluesofx,thenkliesintheinterval

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a

(32,32)

b

(14,14)

c

(12,  12)

d

[32,32]

answer is C.

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Detailed Solution

Given3x2+4kx+1>0x2co.eff=3>0x2co.efficentandexpressionhavesamesigne  D0(4k)24(3)(1)016k21204k230(2k+3)(2k3)0k[32,32]

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