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Q.

If 4a+5b+9c=0, then a×b×b×c×c×a is equal to

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a

a vector perpendicular to the plane of a,b and c

b

a scalar quantity

c

0

d

2

answer is C.

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Detailed Solution

4a+5b+9c=0
         0+5(a×b)+9(a×c)=0
  5(a×b)=9 (c×a)  a×b,  c×a  Parallel
(a×b)×((b×c)×(c×a))=0

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If 4a→+5b→+9c→=0, then a→×b→×b→×c→×c→×a→ is equal to