If $5 sinα = 3 sinβ$ then $\frac{tan (\frac{α + β}{2})}{tan (\frac{α - β}{2})} =$

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-4

-2

answer is D.

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Detailed Solution

$\frac{sinα}{sinα} = \frac{3}{5} \Rightarrow \frac{sinα + sinβ}{sinα - sinβ} = \frac{3 + 5}{3 - 5} \Rightarrow \frac{\tan (\frac{α + β}{2})}{\tan (\frac{α - β}{2})} = - 4$

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