If $\frac{60+x}{400+x}\times 100=32$, then find the value of $\frac{x}{2}+1$

 

 

$$\frac{60+x}{400+x}\times 100=32$$

$$\Rightarrow 100\left(60+x\right)=32\left(400+x\right)$$

$$\Rightarrow 6000+100x=12800+32x$$

$$\Rightarrow 100x-32x=12800-6000$$

$$\Rightarrow 68x=6800$$

$$\Rightarrow x=100$$

Therefore,$\frac{x}{2}+1=\frac{100}{2}+1=51$