If A-2B=1-230 and 2A-3B=-331-1 then B=

A-2B=1-230, 2A-3B=-331-1 2A-4B-(2A-3B)=2-460--331-1 -B=5-751 B=-57-5-1

If A-2B=1-230 and 2A-3B=-331-1 then B=

A-2B=1-230, 2A-3B=-331-1 2A-4B-(2A-3B)=2-460--331-1 -B=5-751 B=-57-5-1

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If $A - 2 B = (\begin{matrix} 1 & - 2 \\ 3 & 0 \end{matrix})$ and $2 A - 3 B = [\begin{matrix} - 3 & 3 \\ 1 & - 1 \end{matrix}]$ then B=

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$(\begin{matrix} - 5 & 7 \\ 5 & 1 \end{matrix})$

$(\begin{matrix} - 5 & 7 \\ - 5 & - 1 \end{matrix})$

$(\begin{matrix} - 5 & 7 \\ 5 & - 1 \end{matrix})$

$(\begin{matrix} - 5 & - 7 \\ - 5 & - 1 \end{matrix})$

answer is B.

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Detailed Solution

$A - 2 B = [\begin{matrix} 1 & - 2 \\ 3 & 0 \end{matrix}], 2 A - 3 B = [\begin{matrix} - 3 & 3 \\ 1 & - 1 \end{matrix}] 2 A - 4 B - (2 A - 3 B) = [\begin{matrix} 2 & - 4 \\ 6 & 0 \end{matrix}] - [\begin{matrix} - 3 & 3 \\ 1 & - 1 \end{matrix}] - B = [\begin{matrix} 5 & - 7 \\ 5 & 1 \end{matrix}] B = [\begin{matrix} - 5 & 7 \\ - 5 & - 1 \end{matrix}]$