If A→ = 4N, B→ = 3N the value of A→ x B→2=A→.B→2 then

A = 4N, B = 3NA¯ x B¯2+A¯.B¯2=A2B2sinθ+A2B2cos2θ=A2B2(sin2θ+cos2θ)=A2B2=(4)2(3)2= 16 x 9 = 144N

If A→ = 4N, B→ = 3N the value of A→ x B→2=A→.B→2 then

A = 4N, B = 3NA¯ x B¯2+A¯.B¯2=A2B2sinθ+A2B2cos2θ=A2B2(sin2θ+cos2θ)=A2B2=(4)2(3)2= 16 x 9 = 144N

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If $\vec{A}$ = 4N, $\vec{B}$ = 3N the value of ${|\vec{A} x \vec{B}|}^{2} = {|\vec{A} . \vec{B}|}^{2}$ then

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5 N

25 N

144 N

169 N

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A = 4N, B = 3N

${|\bar{A} x \bar{B}|}^{2} + {|\bar{A} . \bar{B}|}^{2} = A^{2} B^{2} sinθ + A^{2} B^{2} \cos^{2} θ$

$= A^{2} B^{2} (\sin^{2} θ + \cos^{2} θ) = A^{2} B^{2} = {(4)}^{2} {(3)}^{2}$

= 16 x 9 = 144N

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If A→ = 4N, B→ = 3N the value of A→ x B→2=A→.B→2 then

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If $\vec{A}$ = 4N, $\vec{B}$ = 3N the value of ${|\vec{A} x \vec{B}|}^{2} = {|\vec{A} . \vec{B}|}^{2}$ then